The value of a for which one root of (a²-5a+3)x²+(3a-1)x+2=0 is twice the other is (a) - 13 (b) 23 (c) - 23 (d) 13

Correct answer: (b) 23 Roots r,2r: 9(a²-5a+3)=(3a-1)²→-45a+27=-6a+1→ a= 23. JEE Main 2003 · Quadratic Equations and Inequations — verified solution by the Vidaara Team.

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[JEE Main 2003] the value of a for which one root of a 2 5a 3 x

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The value of $a$ for which one root of $(a^2-5a+3)x^2+(3a-1)x+2=0$ is twice the other is

(a) $-\frac13$
(b) $\frac23$
(c) $-\frac23$
(d) $\frac13$

1 Answer

VAVidaara Admin ✓ Vidaara Team ✓ Accepted · 2d ago ▲ 0

Correct answer: (b) $\frac23$

Roots $r,2r$: $9(a^2-5a+3)=(3a-1)^2\Rightarrow-45a+27=-6a+1\Rightarrow a=\frac23$.

JEE Main 2003 · Quadratic Equations and Inequations — verified solution by the Vidaara Team.

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