Three particles of masses 1 kg, 2 kg, and 3 kg are placed at positions (0,0), (1,0), and (0,1) respectively — JEE Physics
Three particles of masses 1 kg, 2 kg, and 3 kg are placed at positions $(0,0)$, $(1,0)$, and $(0,1)$ respectively. Find the coordinates of the center of mass.
1 Answer
EEthanWalker47
✓ Accepted
· 1mo ago
▲ 21
$$x_{cm} = \frac{m_1x_1 + m_2x_2 + m_3x_3}{m_1+m_2+m_3} = \frac{1(0)+2(1)+3(0)}{6} = \frac{2}{6} = \frac{1}{3}$$
$$y_{cm} = \frac{1(0)+2(0)+3(1)}{6} = \frac{3}{6} = \frac{1}{2}$$
$$\left(\frac{1}{3},\ \frac{1}{2}\right) m$$
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Discussion (3)
P
Underrated solution. The way you set it up makes it almost obvious.
S
Pro tip: memorise the standard result, it reappears in many problems.
PP
This is exactly the kind of step-by-step I needed. Respect.