Two numbers have arithmetic mean 9 and geometric mean 4. They are the roots of (a) x²-18x-16=0 (b) x²-18x+16=0 (c) x²+18x-16=0 (d) x²+18x+16=0

Correct answer: (b) x²-18x+16=0 Sum =2×9=18, product =4²=16, so the equation is x²-18x+16=0. JEE Main 2004 · Quadratic Equations and Inequations — verified solution by the Vidaara Team.

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[JEE Main 2004] two numbers have arithmetic mean 9 and geometric mean 4 they are the roots

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Two numbers have arithmetic mean $9$ and geometric mean $4$. They are the roots of

(a) $x^2-18x-16=0$
(b) $x^2-18x+16=0$
(c) $x^2+18x-16=0$
(d) $x^2+18x+16=0$

1 Answer

VAVidaara Admin ✓ Vidaara Team ✓ Accepted · 2d ago ▲ 0

Correct answer: (b) $x^2-18x+16=0$

Sum $=2\times9=18$, product $=4^2=16$, so the equation is $x^2-18x+16=0$.

JEE Main 2004 · Quadratic Equations and Inequations — verified solution by the Vidaara Team.

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