[JEE Main 2004] Two numbers have arithmetic mean $9$ and geometric mean $4$. They are the roots of
Two numbers have arithmetic mean $9$ and geometric mean $4$. They are the roots of
(a) $x^2-18x-16=0$
(b) $x^2-18x+16=0$
(c) $x^2+18x-16=0$
(d) $x^2+18x+16=0$
1 Answer
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✓ Vidaara Team
✓ Accepted
· 1mo ago
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Correct answer: (b) $x^2-18x+16=0$
Sum $=2\times9=18$, product $=4^2=16$, so the equation is $x^2-18x+16=0$.
JEE Main 2004 · Quadratic Equations and Inequations — verified solution by the Vidaara Team.
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