Two tuning forks have frequencies 256 Hz and 260 Hz — JEE Physics
Two tuning forks have frequencies 256 Hz and 260 Hz. They are sounded simultaneously. Find the number of beats per second and the time interval between successive maximum intensities.
1 Answer
VAVidaara Admin
✓ Vidaara Team
✓ Accepted
· 1mo ago
▲ 36
$$Beat frequency = |f_1 - f_2| = |256 - 260| = 4 beats/s$$
$$Time interval = \frac{1}{4} = 0.25 s$$
Log in to post your own answer or join the discussion.
Discussion (4)
A
For revision — the key formula used here comes up almost every year.
GP
Can someone explain why we ignore the other root here?
AB
Thanks a ton, I was stuck on this exact problem for an hour.
PP
Brilliant explanation, the substitution step is what I kept missing.