[JEE Advanced 1992] x sqrt x 3 1 5 x sqrt x 3 1 5 is a
$\left(x+\sqrt{x^3-1}\right)^5+\left(x-\sqrt{x^3-1}\right)^5$ is a polynomial of degree
(a) $5$
(b) $6$
(c) $7$
(d) $8$
1 Answer
VAVidaara Admin
✓ Vidaara Team
✓ Accepted
· 2d ago
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Correct answer: (c) $7$
Only even powers of $\sqrt{x^3-1}$ survive; the highest term is $2\binom54 x(x^3-1)^2$, of degree $7$.
JEE Advanced 1992 · Binomial Theorem — verified solution by the Vidaara Team.
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