IMOClass 10 › Chapter Test

Introduction to Trigonometry — Chapter Test

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Q1
1 − sin²θ is equal to:
From sin²θ + cos²θ = 1, 1 − sin²θ = cos²θ.
Q2
The maximum possible value of sin θ is:
sin θ ranges from −1 to 1, so its maximum (for 0° to 90°) is 1.
Q3
The value of tan 30° is:
tan 30° = 1/√3.
Q4
The angle of depression of a boat from the top of a 75 m cliff is 45°. The boat is from the foot of the cliff:
PQ45°75 md
tan 45° = 75/d = 1, so d = 75 m.
Q5
tan 90° is:
tan 90° = sin 90°/cos 90° = 1/0, which is not defined.
Q6
A ladder makes a 60° angle with the ground and its foot is 2.5 m from the wall. The ladder's length is:
OBT60°2.5 mladder90°
cos 60° = 2.5/L, so L = 2.5 ÷ 0.5 = 5 m.
Q7
The value of sin 90° is:
sin 90° = 1.
Q8
The value of 2 sin 30° is:
2 × 1/2 = 1.
Q9
sin(90° − θ) equals:
Complementary-angle relation: sin(90° − θ) = cos θ.
Q10
The value of tan 45° is:
tan 45° = 1.
Q11
The value of cos² 45° − sin² 45° is:
Both equal 1/2, so the difference is 0.
Q12
From two points on the same side, in line with a tower's base, the angles of elevation of its top are 30° and 60°. If the points are 40 m apart, the tower's height is:
OBT60° / 30°40 m aparth90°
With h = d tan 60° and h = (d + 40) tan 30°, solving gives d = 20 and h = 20√3 m.
Q13
The value of cos θ when θ = 90° is:
cos 90° = 0.
Q14
The value of sin² 30° + cos² 30° is:
By the identity sin²θ + cos²θ = 1.
Q15
A ramp 12 m long rises at 30° to the horizontal. The height it reaches is:
OBT30°h12 m90°
height = 12 × sin 30° = 12 × 1/2 = 6 m.
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