Let y = cos(tan ) dx = -sin(tan ). ) dx = -sin(tan ).sec 2 . ) dx =-sin(tan ).sec 2 . 2 therefore, dx = - 2 sin(tan ).sec 2 .

Continuity and Differentiability — Class 12 Maths Solution

exemplar sa SA NCERT Exemp. Ex.5.3 ,Q.31,Page 109

Question

cos(tan$\sqrt{x+1}$ )

Step-by-step Solution

Let $y = cos(tan\sqrt{x+1})$

$\frac{dy}{dx} = -sin(tan\sqrt{x+1}). \frac{d(tan\sqrt{x+1})}{dx}$

$= -sin(tan\sqrt{x+1}).sec^2\sqrt{x+1}.\frac{d(\sqrt{x+1})}{dx}$

$=-sin(tan\sqrt{x+1}).sec^2\sqrt{x+1}.\frac{1}{2\sqrt{x+1}}$

therefore, $\frac{dy}{dx} = -\frac{1}{2\sqrt{x+1}}sin(tan\sqrt{x+1}).sec^2\sqrt{x+1}.$

NCERT & Exemplar solution for CBSE Class 12 Mathematics, Continuity and Differentiability. Curated by Sachin Sharma. Free for all students.