If $f(x) = 2x$ and $g(x) = \frac{{{x^2}}}{2} + 1,$ then which of the following can be a discontinuous function?
- (a) $f(x) + g(x)$
- (b) $f(x) - g(x)$
- (c) $f(x) \cdot g(x)$
- (d) $\frac{{g(x)}}{{f(x)}}$ ✓ Correct
If $f(x) = 2x$ and $g(x) = \frac{{{x^2}}}{2} + 1,$ then which of the following can be a discontinuous function?
We know that, if $f$ and $g$ be continuous functions, then
$f + g$ is continuous
$f - g$ is continuous.
$fg$ is continuous
$\frac{f}{g}$ is continuous at these points, where $g(x) \ne 0$.
Here, $\frac{{g(x)}}{{f(x)}} = \frac{{\frac{{{x^2}}}{2} + 1}}{{2x}} = \frac{{{x^2} + 2}}{{4x}}$
which is discontinuous at $x = 0$
NCERT & Exemplar solution for CBSE Class 12 Mathematics, Continuity and Differentiability. Curated by Sachin Sharma. Free for all students.