Continuity and Differentiability — Class 12 Maths Solution

ncert exercise SA NCERT Ex.5.2 ,Q.2,Page 166
Question

cos(sin x)

Step-by-step Solution

Let $y = \cos (\sin x)$

$\Rightarrow$ $\cfrac{{dy}}{{dx}} = \cfrac{d}{{dx}}\cos (\sin x) = - \sin (\sin x)\cfrac{d}{{dx}}\sin x$

$= - \sin (\sin x)\cos x$

therefore $\frac{dy}{dx}= = - \sin (\sin x)\cos x$

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NCERT & Exemplar solution for CBSE Class 12 Mathematics, Continuity and Differentiability. Curated by Sachin Sharma. Free for all students.