Continuity and Differentiability — Class 12 Maths Solution

ncert exercise SA NCERT Ex.5.2 ,Q.3,Page 166
Question

sin(ax + b)

Step-by-step Solution

Let $y = \sin (ax + b)$

$\Rightarrow$ $\cfrac{{dy}}{{dx}} = \cfrac{d}{{dx}}\sin (ax + b) = \cos (ax + b)\cfrac{d}{{dx}}(ax + b)$
$= \cos (ax + b)(a + 0) = a\cos (ax + b)$

therefore $\frac{dy}{dx}=a\cos (ax + b)$

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NCERT & Exemplar solution for CBSE Class 12 Mathematics, Continuity and Differentiability. Curated by Sachin Sharma. Free for all students.