Continuity and Differentiability — Class 12 Maths Solution

ncert exercise SA NCERT Ex.5.4 ,Q.3,Page 174
Question

${e^{{x^3}}}$

Step-by-step Solution

Let $y = {e^{{x^3}}}$

therefore, $\cfrac{{dy}}{{dx}} = \cfrac{d}{{dx}}\left( {{e^{{x^3}}}} \right) = {e^{{x^3}}}\cfrac{d}{{dx}}({x^3}) = {e^{{x^3}}} \cdot 3{x^2} = 3{e^{{x^3}}} \cdot {x^2}$

NCERT & Exemplar solution for CBSE Class 12 Mathematics, Continuity and Differentiability. Curated by Sachin Sharma. Free for all students.