Continuity and Differentiability — Class 12 Maths Solution

ncert exercise SA NCERT Ex.5.7 ,Q.2,Page 183
Question

${x^{20}}$

Step-by-step Solution

Let$y = {x^{20}}$
$\Rightarrow$ $\cfrac{{dy}}{{dx}} = 20{x^{19}}$

therefore,

$\cfrac{{{d^2}y}}{{d{x^2}}} = 20 \cdot 19{x^{18}} = 380{x^{18}}$

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NCERT & Exemplar solution for CBSE Class 12 Mathematics, Continuity and Differentiability. Curated by Sachin Sharma. Free for all students.