Continuity and Differentiability — Class 12 Maths Solution

ncert exercise SA NCERT Ex.5.7 ,Q.4,Page 183
Question

log x

Step-by-step Solution

Let y $=$ log x
$\Rightarrow$ $\cfrac{{dy}}{{dx}} = \cfrac{1}{x}$ therefore,

$\cfrac{{{d^2}y}}{{d{x^2}}} = - \cfrac{1}{{{x^2}}}$

NCERT & Exemplar solution for CBSE Class 12 Mathematics, Continuity and Differentiability. Curated by Sachin Sharma. Free for all students.