Let y = (3 x 2 - 9x + 5) 9 ...(i) Differentiating (i) w.r.t. x, we get dx = 9 (3 x 2 - 9x + 5) 8 (6x - 9) = 27 (3 x 2 - 9x + 5) 8 (2x - 3)

Continuity and Differentiability — Class 12 Maths Solution

ncert misc SA NCERT Misc. ,Q.1,Page 191

Question

${(3{x^2} - 9x + 5)^9}$

Step-by-step Solution

Let$y = {(3{x^2} - 9x + 5)^9}$ ...(i)

Differentiating (i) w.r.t. x, we get
$\cfrac{{dy}}{{dx}} = 9{(3{x^2} - 9x + 5)^8} \cdot (6x - 9) = 27{(3{x^2} - 9x + 5)^8} \cdot (2x - 3)$

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