Continuity and Differentiability — Class 12 Maths Solution

ncert misc SA NCERT Misc. ,Q.2,Page 191
Question

${\sin ^3}x + {\cos ^6}x$

Step-by-step Solution

Let$y = {\sin ^3}x + {\cos ^6}x$ …(i)
Differentiating (i) w.r.t. x, we get

$\cfrac{{dy}}{{dx}} = 3{\sin ^2}x\cos x + 6{\cos ^5}x( - \sin x)$
$= 3\sin x\cos x(\sin x - 2{\cos ^4}x)$

NCERT & Exemplar solution for CBSE Class 12 Mathematics, Continuity and Differentiability. Curated by Sachin Sharma. Free for all students.