Differential Equations — Class 12 Maths Solution

ncert exercise SA NCERT Ex.9.1,Q.3,Page 382
Question

${\left( {\cfrac{{ds}}{{dt}}} \right)^4} + 3s\cfrac{{{d^2}s}}{{d{t^2}}} = 0$

Step-by-step Solution

.: The highest order derivative is
$\cfrac{{{d^2}s}}{{d{t^2}}}$ and the degree of

its highest order is one.

Therefore, the given
differential equation is of order 2 and degree 1.

← All Differential Equations solutions Practice tests →

NCERT & Exemplar solution for CBSE Class 12 Mathematics, Differential Equations. Curated by Sachin Sharma. Free for all students.