Question
${(y''')^2} + {(y'')^3} + {(y')^4} + {y^5} = 0$
${(y''')^2} + {(y'')^3} + {(y')^4} + {y^5} = 0$
.: The highest order derivative is $y'''$ and the degree of its highest order is 2.
Therefore, the given differential equation is of order 3 and degree 2.
NCERT & Exemplar solution for CBSE Class 12 Mathematics, Differential Equations. Curated by Sachin Sharma. Free for all students.