.: We have, y = x + C …(1) Differentiating (1) w.r.t. x , we get y' = - x y' + x = 0 Hence, y = x + C is a solution of the given differential equation.

Differential Equations — Class 12 Maths Solution

ncert exercise SA NCERT Ex.9.2,Q.3,Page 385

Question

$y = \cos x + C:y' + \sin x = 0$

Step-by-step Solution

.: We have, $y = \cos x + C$

…(1)
Differentiating (1) w.r.t. $x$,

we get $y' = - \sin x$
$\Rightarrow y' + \sin x = 0$

Hence, $y = \cos x + C$ is a solution of the

given differential equation.

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NCERT & Exemplar solution for CBSE Class 12 Mathematics, Differential Equations. Curated by Sachin Sharma. Free for all students.