Consider that, I = (x + x) dx Let x + x = t (1 + x)dx = dt therefore, I = t 1 d t = |t| + C = |(x + x)| + C

Integrals — Class 12 Maths Solution

exemplar sa SA NCERT Exemp. Q. 5,Page 164

Question

$\int {\frac{{(1 + \cos x)}}{{x + \sin x}}} dx$

Step-by-step Solution

}

Consider that, $I = \int {\frac{{(1 + \cos x)}}{{(x + \sin x)}}} dx$

Let $x + \sin x = t \Rightarrow (1 + \cos x)dx = dt$

therefore,$I = \int_t^1 d t = \log |t| + C$

$= \log |(x + \sin x)| + C$

NCERT & Exemplar solution for CBSE Class 12 Mathematics, Integrals. Curated by Sachin Sharma. Free for all students.