Let I = x ) 2 dx = x - 2 )dx = 2 + x - 2x + C

Integrals — Class 12 Maths Solution

ncert exercise SA NCERT,ex.7.1,Q.10,Page 299

Question

$\int {{{\left( {\sqrt x - \cfrac{1}{{\sqrt x }}} \right)}^2}dx}$

Step-by-step Solution

Let$I = \int {{{\left( {\sqrt x - \cfrac{1}{{\sqrt x }}} \right)}^2}dx}$

$= \int {\left( {x + \cfrac{1}{x} - 2} \right)dx} = \cfrac{{{x^2}}}{2} + \log x - 2x + C$

NCERT & Exemplar solution for CBSE Class 12 Mathematics, Integrals. Curated by Sachin Sharma. Free for all students.