: Let I = + 5 x 2 - 4 x 2 )dx = )dx = 2 + 5x - - 1 + C = 2 + 5x + x + C

Integrals — Class 12 Maths Solution

ncert exercise SA NCERT,ex.7.1,Q.11,Page 299

Question

$\int {\cfrac{{{x^3} + 5{x^2} - 4}}{{{x^2}}}dx}$

Step-by-step Solution

: Let$I = \int {\left( {\cfrac{{{x^3} + 5{x^2} - 4}}{{{x^2}}}} \right)dx} = \int {\left( {x + 5 - 4{x^{ - 2}}} \right)dx}$

$= \cfrac{{{x^2}}}{2} + 5x - \cfrac{{4{x^{ - 1}}}}{{ - 1}} + C = \cfrac{{{x^2}}}{2} + 5x + \cfrac{4}{x} + C$

NCERT & Exemplar solution for CBSE Class 12 Mathematics, Integrals. Curated by Sachin Sharma. Free for all students.