: Let I = 2 x dx = 2 x - 3 2 x )dx = 2 x - 3 x x )dx = 2 x - 3 x + C Choose the correct answer in Exercises 21 and 22 ;

Integrals — Class 12 Maths Solution

ncert exercise SA NCERT,ex.7.1,Q.20,Page 299

Question

$\int {\cfrac{{2 - 3\sin x}}{{{{\cos }^2}x}}dx}$

Step-by-step Solution

: Let$I = \int {\cfrac{{2 - 3\sin x}}{{{{\cos }^2}x}}dx} = \int {\left( {\cfrac{2}{{{{\cos }^2}x}} - 3\cfrac{{\sin x}}{{{{\cos }^2}x}}} \right)dx}$

$= \int {\left( {2{{\sec }^2}x - 3\sec x\tan x} \right)dx} = 2\tan x - 3\sec x + C$

$figure$

NCERT & Exemplar solution for CBSE Class 12 Mathematics, Integrals. Curated by Sachin Sharma. Free for all students.