Question
$\int {{x^2}\left( {1 - \cfrac{1}{{{x^2}}}} \right)dx}$
$\int {{x^2}\left( {1 - \cfrac{1}{{{x^2}}}} \right)dx}$
: Let$I = \int {{x^2}\left( {1 - \cfrac{1}{{{x^2}}}} \right)dx} = \int {\left( {{x^2} - 1} \right)dx} = \cfrac{{{x^3}}}{3} - x + C$
NCERT & Exemplar solution for CBSE Class 12 Mathematics, Integrals. Curated by Sachin Sharma. Free for all students.