Integrals — Class 12 Maths Solution

.: Let$I = \int {\sqrt {ax + b} d} x = \int {{{\left( {ax + b} \right)}^{1/2}}dx}$

$= \cfrac{{{{\left( {ax + b} \right)}^{3/2}}}}{{\cfrac{3}{2}a}} + C = \cfrac{2}{{3a}}{\left( {ax + b} \right)^{3/2}} + C$