Question
$\int\limits_0^{\pi /2} {\cos 2x} \,dx$
Integrals — Class 12 Maths Solution
Step-by-step Solution
$\int\limits_0^{\pi /2} {\cos 2x} \,dx = \left[ {\cfrac{1}{2}\sin 2x} \right]_0^{\pi /2}$
$= \cfrac{1}{2}\left( {\sin \pi - \sin 0} \right) = \cfrac{1}{2}\left( {0 - 0} \right) = 0$
NCERT & Exemplar solution for CBSE Class 12 Mathematics, Integrals. Curated by Sachin Sharma. Free for all students.