Inverse Trigonometric Functions — Class 12 Maths Solution

exemplar sa SA NCERT,Ex.2.3,Q.2,Page.35
Question

Evaluate $\cos \left[ {{{\cos }^{ - 1}}\left( {\frac{{ - \sqrt 3 }}{2}} \right) + \frac{\pi }{6}} \right]$.

Step-by-step Solution

We have, $\cos \left[ {{{\cos }^{ - 1}}\left( {\frac{{ - \sqrt 3 }}{2}} \right) + \frac{\pi }{6}} \right] = \cos \left[ {{{\cos }^{ - 1}}\left( {\cos \frac{{5\pi }}{6}} \right) + \frac{\pi }{6}} \right]$

$= \cos \left( {\frac{{5\pi }}{6} + \frac{\pi }{6}} \right)$

$= \cos \left( {\frac{{6\pi }}{6}} \right)$
$= \cos (\pi ) = - 1$

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NCERT & Exemplar solution for CBSE Class 12 Mathematics, Inverse Trigonometric Functions. Curated by Sachin Sharma. Free for all students.