The set of values of ${\sec ^{ - 1}}\frac{1}{2}$ is
Inverse Trigonometric Functions — Class 12 Maths Solution
Question
Step-by-step Solution
Since, domain of ${\sec ^{ - 1}}x$ is $R - ( - 1,1)$.
$\Rightarrow$ $( - \infty , - 1] \cup [1,\infty )$
So, there is no set of values exist for ${\sec ^{ - 1}}\frac{1}{2}$.
So, $\phi$ is the answer.
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