Inverse Trigonometric Functions — Class 12 Maths Solution

exemplar fill FillBlank NCERT,Ex.2.3,Q.45,Page.40
Question

The value of $\tan \left( {\frac{{{{\sin }^{ - 1}}x + {{\cos }^{ - 1}}x}}{2}} \right)$, when $x = \frac{{\sqrt 3 }}{2}$, is …………..

Step-by-step Solution

$\tan \left( {\frac{{{{\sin }^{ - 1}}x + {{\cos }^{ - 1}}x}}{2}} \right) = \tan \left( {\frac{{\pi /2}}{2}} \right)$

$= \tan \frac{\pi }{1} = 1$

NCERT & Exemplar solution for CBSE Class 12 Mathematics, Inverse Trigonometric Functions. Curated by Sachin Sharma. Free for all students.