The value of $\tan \left( {\frac{{{{\sin }^{ - 1}}x + {{\cos }^{ - 1}}x}}{2}} \right)$, when $x = \frac{{\sqrt 3 }}{2}$, is …………..
Inverse Trigonometric Functions — Class 12 Maths Solution
Question
Step-by-step Solution
$\tan \left( {\frac{{{{\sin }^{ - 1}}x + {{\cos }^{ - 1}}x}}{2}} \right) = \tan \left( {\frac{{\pi /2}}{2}} \right)$
$= \tan \frac{\pi }{1} = 1$
NCERT & Exemplar solution for CBSE Class 12 Mathematics, Inverse Trigonometric Functions. Curated by Sachin Sharma. Free for all students.