The result - 1 x - - 1 y = - 1 ( 1 + xy ) is true when the value of xy is………………..

We know that, - 1 x - - 1 y = - 1 ( 1 + xy ) where, xy > - 1

Inverse Trigonometric Functions — Class 12 Maths Solution

exemplar fill FillBlank NCERT,Ex.2.3,Q.47,Page.40

Question

The result ${\tan ^{ - 1}}x - {\tan ^{ - 1}}y = {\tan ^{ - 1}}\left( {\frac{{x - y}}{{1 + xy}}} \right)$ is true when the value of $xy$ is………………..

Step-by-step Solution

We know that, ${\tan ^{ - 1}}x - {\tan ^{ - 1}}y = {\tan ^{ - 1}}\left( {\frac{{x - y}}{{1 + xy}}} \right)$
where, $xy > - 1$

NCERT & Exemplar solution for CBSE Class 12 Mathematics, Inverse Trigonometric Functions. Curated by Sachin Sharma. Free for all students.