Find the values of a, b, c and d from the equation :
$\left[ {\begin{array}{cccccccccccccccccccc}{a - b}&{2a + c}\\{2a - b}&{3c + d}\end{array}} \right] = \left[ {\begin{array}{cccccccccccccccccccc}{ - 1}&5\\0&{13}\end{array}} \right]$
.:
From the given matrix, we have
a$-$ b =$-$1 (i) and 2a$-$b = 0 .... (ii)
Solving (i) \& (ii), we get a = 1 and b = 2
Similarly 2a + c = 5 $\Rightarrow$ 2 × 1 + c = 5 $\Rightarrow$ c = 3
Also, 3c + d = 13
$\Rightarrow$ 3 × 3 + d = 13 $\Rightarrow$ d = 4
Hence, a = 1, b = 2, c = 3, d= 4.
NCERT & Exemplar solution for CBSE Class 12 Mathematics, Matrices. Curated by Sachin Sharma. Free for all students.