The restriction on n, k and p so that PY + WY will be defined are $\cdots$
- (a) k = 3, p= n
- (b) k is arbitrary, p = 2
- (c) p is arbitrary, k = 3
- (d) k = 2, p= 3
The restriction on n, k and p so that PY + WY will be defined are $\cdots$
.:
Option a is correct
Given : $X_{2 \times n},Y_{3 \times k},Z_{2 \times p},W_{n \times 3},P_{p \times k}$
Now, $PY + WY = {P_{p \times k}} \times {Y_{3 \times k}} + {Q_{n \times 3}} \times {Y_{3 \times k}}$
Clearly, k = 3 and p = n
NCERT & Exemplar solution for CBSE Class 12 Mathematics, Matrices. Curated by Sachin Sharma. Free for all students.