If $P(A) = \frac{7}{{13}}$, $P(B) = \frac{9}{{13}}$ and $P(A \cap B) = \frac{4}{{13}}$, then $P\left( {{A^\prime }/B} \right)$ is equal to
- (a) $\frac{6}{{13}}$
- (b) $\frac{4}{{13}}$
- (c) $\frac{4}{9}$
- (d) $\frac{5}{9}$ ✓ Correct
If $P(A) = \frac{7}{{13}}$, $P(B) = \frac{9}{{13}}$ and $P(A \cap B) = \frac{4}{{13}}$, then $P\left( {{A^\prime }/B} \right)$ is equal to
Here, $P(A) = \frac{7}{{13}},P(B) = \frac{9}{{13}}$ and $P(A \cap B) = \frac{4}{{13}}$
$\therefore$ $P\left( {{A^\prime }/B} \right) = \frac{{P\left( {{A^\prime } \cap B} \right)}}{{P(B)}} = \frac{{P(B) - P(A \cap B)}}{{P(B)}}$
$= \frac{{\frac{9}{{13}} - \frac{4}{{13}}}}{{\frac{9}{{13}}}} = \frac{{\frac{5}{{13}}}}{{\frac{9}{{13}}}} = \frac{5}{9}$
NCERT & Exemplar solution for CBSE Class 12 Mathematics, Probability. Curated by Sachin Sharma. Free for all students.