Probability — Class 12 Maths Solution

exemplar objective MCQ NCERT,Exemp,Q.88,Page.284
Question

For the following probability distribution.
X -4 -3 -2 -1 0
P(X) 0.1 0.2 0.3 0.2 0.2
$E(X)$ is equal to

  • (a) 0
  • (b) -1
  • (c) -2
  • (d) -1.8 ✓ Correct
Step-by-step Solution
Correct answer: option (d)

$E(X) = \Sigma XP(X)$
$= - 4 \times (0.1) + ( - 3 \times 0.2) + ( - 2 \times 0.3) + ( - 1 \times 0.2) + (0 \times 0.2)$

$= - 0.4 - 0.6 - 0.6 - 0.2 = - 1.8$

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NCERT & Exemplar solution for CBSE Class 12 Mathematics, Probability. Curated by Sachin Sharma. Free for all students.