Relations and Functions — Class 12 Maths Solution

ncert exercise SA NCERT Ex. 1.3,Q.2, Page 18
Question

Let f, g and h be functions from R to R. Show that
$(f+g)oh = foh +goh$

Step-by-step Solution

First, we show that $(f + g)oh = foh + goh$

L.H.S. $=$ $(f + g)oh = (f + g)[h(x)]$ $= f[h(x)] + g[h(x)] = foh + goh = R.H.S.$
Now, we show that $(f \cdot g)oh = (foh) \cdot (goh)$

L.H.S. $=$ $(f \cdot g)oh = (f \cdot g)[h(x)] = f[h(x)] \cdot g[h(x)] = (foh) \cdot (goh) = R.H.S.$

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NCERT & Exemplar solution for CBSE Class 12 Mathematics, Relations and Functions. Curated by Sachin Sharma. Free for all students.