Three Dimensional Geometry — Class 12 Maths Solution

ncert misc SA NCERT,Misc,Q.16, Page .498
Question

If O be the origin and the coordinates of P be $(1,2, - 3)$, then, find the equation of the plane passing through P and perpendicular to O P.

Step-by-step Solution

The direction ratios of OP are $< 1 - 0,2 - 0, - 3 - 0 >$ i.e. $< 1,2, - 3 >$

$\therefore$ The equation of the plane passing through P and perpendicular to OP is
$(1)(x - 1) + (2)(y - 2) + ( - 3)(z + 3) = 0$

$\Rightarrow$ $x - 1 + 2y - 4 - 3z - 9 = 0 \Rightarrow x + 2y - 3z - 14 = 0$

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NCERT & Exemplar solution for CBSE Class 12 Mathematics, Three Dimensional Geometry. Curated by Sachin Sharma. Free for all students.