Vector Algebra — Class 12 Maths Solution

Required vector $= ( - 3 - 2)\widehat {\rm{i}} + (7 - 5)\widehat {\rm{j}} + (4 - 0)\widehat {\rm{k}}$

$= - 5\widehat {\rm{i}} + 2\widehat {\rm{j}} + 4\widehat {\rm{k}}$

Similarly, we can say that for having initial and terminal points as

(i) $$\left( {4,1,1} \right)$$ and $(3,13,5)$, respectively.

(ii) $$\left( {1,1,9} \right)$$ and $(6,3,5)$, respectively.

(iii) $$\left( {1,2,3} \right)$$ and $(2,3,4)$, respectively, we shall get (a), (b) and (d) as its correct options.