If $|\overrightarrow {\rm{a}} | = 4$ and $- 3 \le \lambda \le 2$, then the range of $|\lambda \overrightarrow {\rm{a}} |$ is
- (a) $[0,8]$
- (b) $[-12,8]$
- (c) $[0,12]$ ✓ Correct
- (d) $[8,12]$
If $|\overrightarrow {\rm{a}} | = 4$ and $- 3 \le \lambda \le 2$, then the range of $|\lambda \overrightarrow {\rm{a}} |$ is
We have, $|\vec a| = 4$ and $- 3 \le \lambda \le 2$
$\therefore$
$\Rightarrow$ $|\lambda \overrightarrow {\rm{a}} | = | - 3|4 = 12$, at $\lambda = - 3$
$|\lambda \vec a| = |0|4 = 0$, at $\lambda = 0$
and $|\lambda \overrightarrow {\rm{a}} | = |2|4 = 8$, at $\lambda = 2$
So, the range of $|\lambda \overrightarrow {\rm{a}} |$ is [0,12] .
Alternate Method
Since, $- 3 \le \lambda \le 2$
$0 \le |\lambda | \le 3$
$\Rightarrow$ $0 \le 4|\lambda | \le 12$
$|\lambda \overrightarrow {\rm{a}} | \in [0,12]$
NCERT & Exemplar solution for CBSE Class 12 Mathematics, Vector Algebra. Curated by Sachin Sharma. Free for all students.