The p-Block Elements (Group 13 & 14) • Topic 3 of 3

Anomalies & Important Compounds

Two grand themes tie Groups 13 and 14 together: the inert pair effect that governs oxidation-state stability, and the anomalous behaviour of the first member (boron, carbon) compared with its heavier congeners. A third recurring idea — the diagonal relationship — links the first element of each group with the second element of the next group.

The inert pair effect. Heavy p-block elements have an outer ns2npx configuration. As we descend a group, the ns2 (‘inert’) electrons become increasingly reluctant to participate in bonding. The reason is two-fold: the intervening d- and f-electrons shield the ns2 pair poorly, so it is held tightly; and the M-X bond energy falls down the group, so the energy released by forming two extra bonds no longer compensates for the energy needed to unpair and promote the ns2 electrons. The result is that the lower oxidation state (+1 in Group 13, +2 in Group 14) becomes more stable as we go down: Tl+ > Tl3+ in stability, and Pb2+ > Pb4+. Consequently the higher-state species of the heavy elements (Tl3+, Pb4+) are good oxidising agents.

Anomalous behaviour of boron and carbon. The first member of each p-block group differs from the rest because of its small atomic size, high ionisation enthalpy and electronegativity, and the absence of valence d-orbitals. For boron: it is a metalloid (the others are metals), forms only covalent and electron-deficient compounds (Lewis acids like BF3), and has a maximum covalency of 4 (it cannot expand its octet). For carbon: it shows the strongest catenation, forms stable pπ-pπ multiple bonds (so CO2 is molecular while SiO2 is a network), and is limited to a covalency of 4.

Diagonal relationships. Because moving right increases and moving down decreases the same properties (size, electronegativity, charge density), the first element of a group resembles the second element of the next group lying diagonally below-right. Thus boron resembles silicon: both are hard, refractory metalloids, form weakly acidic oxides (B2O3, SiO2), volatile covalent halides hydrolysed by water, and macromolecular hydrides/oxides. (Similarly, in nearby groups, lithium resembles magnesium and beryllium resembles aluminium.)

Group 13 vs Group 14 — a comparison. Group 13 has three valence electrons (ns2np1), shows +3 and (lower down) +1, and its trihalides/hydrides tend to be electron-deficient Lewis acids. Group 14 has four valence electrons (ns2np2), shows +4 and (lower down) +2, and its tetravalent compounds are electron-precise. Both groups show the non-metal-to-metal trend down the column, both have anomalous first members, and both obey the inert pair effect in the heavier elements.

Uses worth remembering. Boron compounds: borax (washing, glass, borosilicate Pyrex), boric acid (mild antiseptic), boron filaments (light, stiff composites). Aluminium: aircraft, cables, foil, thermite welding. Carbon: diamond (abrasives, jewellery), graphite (electrodes, lubricant, pencil ‘lead’), activated charcoal (adsorbent). Silicon: semiconductors and computer chips; silica and silicates in glass and ceramics; silicones as sealants; zeolites as catalysts and water softeners; tin and lead in solders, alloys and storage batteries.

Comparison of Group 13 and Group 14
FeatureGroup 13 (Boron family)Group 14 (Carbon family)
MembersB, Al, Ga, In, TlC, Si, Ge, Sn, Pb
Valence configurationns2np1ns2np2
Valence electrons34
Common oxidation state+3 (also +1 lower down)+4 (also +2 lower down)
Lower state by inert pair effect+1 (Tl mainly +1)+2 (Pb mainly +2)
Anomalous first memberBoron (metalloid, covalency 4)Carbon (catenation, pπ-pπ bonds)
Diagonal relationshipB resembles SiC is the diagonal partner of B
Typical compoundsBF3, B2H6, borax, Al2O3CO, CO2, SiO2, silicones, PbCl2
1
Worked Example
State the inert pair effect and name the most stable oxidation states of Tl and Pb.
Solution
  1. The inert pair effect is the reluctance of the ns2 electrons to take part in bonding for heavy p-block elements.
  2. So the lower oxidation state grows more stable down a group.
  3. For Group 13 this favours +1 and for Group 14 it favours +2.

Answer: Inert pair effect = reluctance of ns2 electrons to bond; the most stable states are Tl+ (+1) and Pb2+ (+2).

2
Worked Example
Give three points to show that boron resembles silicon (diagonal relationship).
Solution
  1. Both are hard, high-melting metalloids that form covalent compounds.
  2. Both form weakly acidic oxides (B2O3 and SiO2) and macromolecular structures.
  3. Both form volatile covalent halides (BCl3, SiCl4) that are readily hydrolysed by water.

Answer: Both are covalent metalloids, give weakly acidic oxides, and form easily hydrolysed volatile chlorides — a classic diagonal relationship.

3
Worked Example
Why is Pb4+ a strong oxidising agent whereas Sn2+ is a reducing agent?
Solution
  1. For Pb the inert pair effect makes +2 the stable state, so Pb4+ tends to gain electrons to become Pb2+ — it oxidises others.
  2. For Sn the +4 state is the more stable one.
  3. So Sn2+ tends to lose electrons to become Sn4+ — it reduces others.

Answer: Pb4+ readily drops to the stable Pb2+ (hence oxidising), while Sn2+ readily rises to the stable Sn4+ (hence reducing).

4
Worked Example
List three reasons why the first member of a p-block group behaves anomalously.
Solution
  1. It has a much smaller atomic size than the others.
  2. It has higher ionisation enthalpy and electronegativity.
  3. It lacks valence d-orbitals, limiting its maximum covalency to four.

Answer: Small size, high IE/electronegativity, and absence of valence d-orbitals (so covalency is restricted to 4) make boron and carbon anomalous.

5
Worked Example
Compare the common and lower oxidation states of Group 13 and Group 14 elements.
Solution
  1. Group 13 (ns2np1): common +3, lower +1.
  2. Group 14 (ns2np2): common +4, lower +2.
  3. In both, the lower state is stabilised down the group by the inert pair effect.

Answer: Group 13 shows +3 (and +1); Group 14 shows +4 (and +2); the lower state dominates for the heaviest members (Tl+, Pb2+).

6
Worked Example
State one important use each of borax, aluminium, graphite and zeolites.
Solution
  1. Borax: making borosilicate (Pyrex) glass and as a flux/cleaning agent.
  2. Aluminium: lightweight alloys for aircraft and electrical cables.
  3. Graphite: electrodes and as a dry lubricant.
  4. Zeolites: catalysts and ion-exchangers for water softening.

Answer: Borax → borosilicate glass/flux; aluminium → aircraft alloys/cables; graphite → electrodes/lubricant; zeolites → cracking catalysts/water softeners.

Key Points

  • Inert pair effect: the ns2 electrons of heavy p-block elements resist bonding (poor d/f shielding + weaker bonds), so lower states grow stable down a group — +1 in Group 13 (Tl+), +2 in Group 14 (Pb2+).
  • Tl3+ and Pb4+ are strong oxidising agents; Sn2+ is a reducing agent.
  • First-member anomaly (B, C): small size, high IE/electronegativity, no valence d-orbitals → covalency limited to 4; B forms electron-deficient Lewis acids, C catenates and forms pπ-pπ bonds.
  • Diagonal relationship: boron resembles silicon (both covalent metalloids, weakly acidic oxides, easily hydrolysed volatile chlorides).
  • Group 13 vs 14: 3 vs 4 valence electrons; +3/+1 vs +4/+2; both show non-metal-to-metal trend and the inert pair effect; key uses span glass, alloys, semiconductors, catalysts and lubricants.
Tap an option to check your answer0 / 4
Q1.The inert pair effect explains why, down a group, the:
Explanation: The ns2 electrons resist bonding, so the lower oxidation state (+1 in Group 13, +2 in Group 14) becomes more stable down the group.
Q2.Boron shows a diagonal relationship with:
Explanation: Boron resembles silicon (diagonally placed): both are covalent metalloids with weakly acidic oxides and easily hydrolysed chlorides.
Q3.Which species is a strong oxidising agent because of the inert pair effect?
Explanation: Pb4+ readily accepts electrons to revert to the more stable Pb2+, so it is a strong oxidising agent.
Q4.The first member of each p-block group is anomalous mainly because it:
Explanation: Small size, high ionisation enthalpy/electronegativity and absence of valence d-orbitals (covalency limited to 4) cause the anomalous behaviour of B and C.