JEE Main Level

Mock Test 1 — Trigonometry

15 questions • 45 minutes • auto-graded with full solutions
45:00
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Section A — MCQ (Single Correct)
Question 1
If $\sin\theta = \dfrac{12}{13}$ and $\theta$ is acute, then $\cos\theta + \tan\theta$ equals:
Question 2
The value of $\tan 9° - \tan 27° - \tan 63° + \tan 81°$ is:
Question 3
The general solution of $\cos 2\theta = -\dfrac{1}{2}$ is:
Question 4
The value of $\sin^{-1}\dfrac{4}{5} + \sin^{-1}\dfrac{3}{5}$ is:
Question 5
In a triangle, if $a = 5$, $b = 12$, $c = 13$, then the radius of the circumscribed circle is:
Question 6
If $\tan A + \tan B + \tan C = \tan A \tan B \tan C$ in a triangle, then $A + B + C$ equals:
Question 7
The number of solutions of $2\sin^2\theta - 5\sin\theta + 2 = 0$ in $[0, 2\pi]$ is:
Question 8
If $\cos x = \dfrac{1}{3}$, $0 < x < \pi$, then $\tan(x/2)$ equals:
Question 9
The angle of elevation of a cloud above a lake from a point $20$ m above the surface is $30°$. The angle of depression of its reflection in the lake from the same point is $60°$. The height of the cloud above the lake is:
Question 10
If $A + B + C = \pi$ in a triangle, then $\cos A + \cos B + \cos C$ equals:
Section B — Integer Type
Question 11 &mdash; Integer answer
If $\sin\theta + \sin^2\theta = 1$, then the value of $\cos^2\theta + \cos^4\theta$ equals which integer?
Enter an integer value.
Question 12 &mdash; Integer answer
In a triangle with sides $a, b, c$ and area $\Delta$, if $a = 6$, $b = 8$, $c = 10$, find $\Delta$.
Enter an integer value.
Question 13 &mdash; Integer answer
The number of solutions of $\sin x \cdot \sin 2x \cdot \sin 3x = 0$ in $[0, \pi]$ is.
Enter an integer value.
Section C — Assertion & Reasoning
Question 14 &mdash; Assertion / Reason
Assertion (A): $\sin^{-1}(\sin 3) = 3$.
Reason (R): For all $x \in \mathbb{R}$, $\sin^{-1}(\sin x) = x$.
Solution: A is false ($.
Question 15 &mdash; Assertion / Reason
Assertion (A): In any triangle, $\dfrac{a}{\sin A} = \dfrac{b}{\sin B} = \dfrac{c}{\sin C}$.
Reason (R): The sine rule is derived using the fact that the diameter of the circumscribed circle equals $\dfrac{a}{\sin A}$.
Solution: Both A and R are true, and R is the correct explanation.