NEET (UG)

Practice Test 1 — Kinematics

12 questions • 18 minutes • auto-graded with full solutions
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Section A — MCQ (Single Correct)
Question 1

A particle covers half its total path in the last second of its free fall from rest. Approximately how long does it fall? (treat conceptually)

Solution: Setting the last-second distance equal to half the total leads to $t \approx 3.4\ \text{s}$; the key idea is distance in free fall grows as $t^2$.
Question 2

A car accelerates uniformly from $10\ \text{m/s}$ to $30\ \text{m/s}$ in $4\ \text{s}$. Its acceleration is:

Solution: $a = (30-10)/4 = 5\ \text{m/s}^2$.
Question 3

The displacement of a body is zero. The distance covered:

Solution: A body may return to start (distance > 0) or never move (distance = 0).
Question 4

A stone is thrown up at $g = 10\ \text{m/s}^2$ with $20\ \text{m/s}$. Time to reach the top:

Solution: $t = u/g = 20/10 = 2\ \text{s}$.
Question 5

The resultant of two perpendicular vectors $6$ and $8$ is:

Solution: $\sqrt{6^2+8^2} = 10$.
Question 6

For a projectile, doubling the speed of projection (same angle) changes the range by a factor of:

Solution: $R \propto u^2$, so doubling $u$ gives $4\times$ range.
Question 7

A swimmer wants to cross a river straight across. He should aim:

Solution: Aiming partly upstream cancels the current's drift.
Question 8

The area under a velocity-time graph between $t_1$ and $t_2$ gives the:

Solution: Area under v–t = displacement.
Section B — Assertion & Reason
Question 9

A: A body can have zero velocity and non-zero acceleration at an instant.
R: At the highest point of vertical projection, velocity is zero but acceleration equals $g$.

Solution: The top-of-throw case is exactly the situation that makes A true.
Question 10

A: Two complementary angles of projection give the same maximum height.
R: Maximum height depends on $\sin^2\theta$.

Solution: Complementary angles give the same RANGE, not the same height; height depends on $\sin^2\theta$ which differs — so A is false, R is true.
Question 11

A: Horizontal and vertical motions of a projectile are independent.
R: Gravity has no horizontal component.

Solution: With no horizontal force, the horizontal motion is unaffected by the vertical — R explains A.
Question 12

A: Average speed is always greater than or equal to the magnitude of average velocity.
R: Distance is always greater than or equal to the magnitude of displacement.

Solution: Dividing distance ≥ |displacement| by the same time gives the speed relation — R explains A.