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Vidaara.orgClass 10 · Physics
CodeVID-P10-03-CUR-01
Electric Current, Potential & Ohm's Law — Assignment
Chapter: Electricity
Topic: Electric Current, Potential & Ohm's Law
Maximum Marks: 30
Time: 60 minutes
Name: ____________________ Roll No.: __________ Date: ____________

General Instructions

  • All questions are compulsory.
  • Section A carries 1 mark each, Section B 2 marks, Section C 3 marks and Section D 5 marks.
  • Show all working for Sections B, C and D. Only final answers are given at the end — for full solutions, raise your doubts with your teacher.
Section A — Multiple Choice Questions 5 × 1 = 5 marks
1.
The SI unit of charge is the:
  • A.ampere
  • B.coulomb
  • C.volt
  • D.ohm
2.
$1\ \text{V}$ equals:
  • A.$1\ \text{J/C}$
  • B.$1\ \text{C/s}$
  • C.$1\ \text{A}\cdot\Omega^{-1}$
  • D.$1\ \text{J/s}$
3.
An ammeter is connected in:
  • A.parallel
  • B.series
  • C.either way
  • D.across the cell
4.
If $V=10\ \text{V}$ and $R=5\ \Omega$, the current is:
  • A.$0.5\ \text{A}$
  • B.$2\ \text{A}$
  • C.$5\ \text{A}$
  • D.$50\ \text{A}$
5.
A non-ohmic device is:
  • A.a metal wire
  • B.a filament bulb
  • C.a constant resistor
  • D.a copper rod
Section B — Short Answer (2 marks) 3 × 2 = 6 marks
6.
A charge of 20 C flows in 4 s. Find the current.
7.
State Ohm's law and write its mathematical form.
8.
Find the work done to move 3 C across a P.D. of 8 V.
Section C — Short Answer (3 marks) 2 × 3 = 6 marks
9.
A 12 V battery drives 0.4 A through a resistor. Find $R$.
10.
How many electrons make up a charge of 2 C? ($e=1.6\times10^{-19}$ C)
Section D — Long Answer (5 marks) 1 × 5 = 5 marks
11.
Draw a circuit with a cell, key, resistor, ammeter and voltmeter. Explain how each meter is connected and how you would verify Ohm's law from a V–I graph.

Answer Key

Section A — Multiple Choice Questions
  1. (B) coulomb
  2. (A) $1\ \text{J/C}$
  3. (B) series
  4. (B) $2\ \text{A}$
  5. (B) a filament bulb
Section B — Short Answer (2 marks)
  1. $5\ \text{A}$.
  2. At constant temperature $V \propto I$, so $V=IR$.
  3. $24\ \text{J}$.
Section C — Short Answer (3 marks)
  1. $R=30\ \Omega$.
  2. $1.25\times10^{19}$ electrons.
Section D — Long Answer (5 marks)
  1. Ammeter in series, voltmeter in parallel across R; a straight-line V–I graph through the origin (slope $=R$) verifies $V=IR$.
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