Electricity • Topic 1 of 3

Electric Current, Potential & Ohm's Law

Electric charge in motion is the heart of electricity. When tiny charged particles (electrons) drift through a conductor like copper wire, we say a current flows. The amount of charge is measured in coulombs (C), where one electron carries a charge of about $1.6 \times 10^{-19}$ C.

Electric current is the rate of flow of charge. If a charge $Q$ flows through any cross-section of a wire in time $t$, then the current is $I=\frac{Q}{t}$. The SI unit of current is the ampere (A), where $1\ \text{A}=1\ \text{C/s}$. By the old convention, the direction of conventional current is taken opposite to the direction of electron flow — current goes from the positive terminal to the negative terminal in the external circuit.

Potential difference is what pushes charge around a circuit. It is the work done to move a unit charge between two points: $V=\frac{W}{Q}$. Its SI unit is the volt (V), where $1\ \text{V}=1\ \text{J/C}$. A cell or battery acts like a pump that maintains this potential difference. We measure current with an ammeter (connected in series) and potential difference with a voltmeter (connected in parallel across the component).

Ohm's law connects current and potential difference. At constant temperature, the current through a conductor is directly proportional to the potential difference across it:

  • $V \propto I$, so $V=IR$, where $R$ is the resistance of the conductor.
  • Resistance is the property that opposes the flow of current; its SI unit is the ohm ($\Omega$), where $1\ \Omega = 1\ \text{V/A}$.
  • Rearranging gives $I=\frac{V}{R}$ and $R=\frac{V}{I}$.

For an ohmic conductor (like a metal wire at constant temperature), the V–I graph is a straight line through the origin, and its slope equals $R$. Non-ohmic devices such as a filament bulb, diode or LED do not obey Ohm's law — their V–I graph is curved because resistance changes with temperature or voltage.

Cell, resistor, ammeter (series) and voltmeter (parallel) circuitCell+-ARVAmmeter (series)Voltmeter (parallel)Conventional current: + to - in external circuit
1
Worked Example
A charge of 60 C flows through a wire in 2 minutes. Calculate the electric current.
Solution
  1. Step 1: Convert time to seconds: $t=2\ \text{min}=120\ \text{s}$.
  2. Step 2: Use $I=\frac{Q}{t}=\frac{60}{120}$.
  3. Step 3: Compute: $I=0.5\ \text{A}$.

Answer: $I=0.5\ \text{A}$

2
Worked Example
How many electrons flow through a conductor when a current of 1 A flows for 1 second? (charge on one electron $=1.6 \times 10^{-19}$ C)
Solution
  1. Step 1: Find total charge: $Q=I \times t=1 \times 1=1\ \text{C}$.
  2. Step 2: Number of electrons $n=\frac{Q}{e}=\frac{1}{1.6 \times 10^{-19}}$.
  3. Step 3: Compute: $n=6.25 \times 10^{18}$ electrons.

Answer: $6.25 \times 10^{18}$ electrons

3
Worked Example
How much work is done in moving a charge of 5 C across two points having a potential difference of 12 V?
Solution
  1. Step 1: Use $V=\frac{W}{Q}$, so $W=V \times Q$.
  2. Step 2: Substitute: $W=12 \times 5$.
  3. Step 3: Compute: $W=60\ \text{J}$.

Answer: $W=60\ \text{J}$

4
Worked Example
A potential difference of 6 V is applied across a resistor and a current of 0.3 A flows. Find the resistance.
Solution
  1. Step 1: By Ohm's law $R=\frac{V}{I}$.
  2. Step 2: Substitute: $R=\frac{6}{0.3}$.
  3. Step 3: Compute: $R=20\ \Omega$.

Answer: $R=20\ \Omega$

5
Worked Example
A resistor of 25 ohm is connected to a 5 V battery. What current flows through it?
Solution
  1. Step 1: By Ohm's law $I=\frac{V}{R}$.
  2. Step 2: Substitute: $I=\frac{5}{25}$.
  3. Step 3: Compute: $I=0.2\ \text{A}$.

Answer: $I=0.2\ \text{A}$

6
Worked Example
The V–I graph of a conductor is a straight line through the origin passing through the point (4 V, 0.5 A). Find its resistance and state whether it is ohmic.
Solution
  1. Step 1: Resistance is the slope reciprocal: $R=\frac{V}{I}$.
  2. Step 2: Substitute: $R=\frac{4}{0.5}=8\ \Omega$.
  3. Step 3: Since the graph is a straight line through the origin, $R$ is constant, so the conductor obeys Ohm's law (it is ohmic).

Answer: $R=8\ \Omega$; the conductor is ohmic.

Key Points

  • Electric current is the rate of flow of charge: $I=\frac{Q}{t}$, measured in amperes (A).
  • Potential difference is work per unit charge: $V=\frac{W}{Q}$, measured in volts (V).
  • Ohm's law: at constant temperature $V=IR$; resistance is measured in ohms ($\Omega$).
  • Ammeter is connected in series and voltmeter in parallel with the component.
  • Ohmic conductors give a straight-line V–I graph through the origin; bulbs and diodes are non-ohmic.
Tap an option to check your answer0 / 4
Q1.The SI unit of electric current is the:
Explanation: Current is measured in amperes (A); $1\ \text{A}=1\ \text{C/s}$.
Q2.If 30 C of charge flows in 10 s, the current is:
Explanation: $I=\frac{Q}{t}=\frac{30}{10}=3\ \text{A}$.
Q3.A voltmeter is always connected:
Explanation: A voltmeter measures potential difference and is connected in parallel.
Q4.For an ohmic conductor, the V–I graph is:
Explanation: Ohm's law gives $V \propto I$, a straight line through the origin whose slope is $R$.