$sin(x^2 + 5)$
$sin(x^2 + 5)$
Official Solution
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NCERT & Exemplar
Let $y = \sin ({x^2} + 5)$
$\Rightarrow$ $\cfrac{{dy}}{{dx}} = \cfrac{d}{{dx}}\sin ({x^2} + 5) = \cos ({x^2} + 5)\cfrac{d}{{dx}}({x^2} + 5)$
$= \cos ({x^2} + 5)(2x + 0) = 2x\cos ({x^2} + 5)$
therefore $\frac{dy}{dx}=\cos ({x^2} + 5)(2x + 0) = 2x\cos ({x^2} + 5)$
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