class 12 maths continuity and differentiability

${e^{{x^3}}}$

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📘 Continuity and Differentiability NCERT Ex.5.4 ,Q.3,Page 174 SA

${e^{{x^3}}}$

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Let $y = {e^{{x^3}}}$

therefore, $\cfrac{{dy}}{{dx}} = \cfrac{d}{{dx}}\left( {{e^{{x^3}}}} \right) = {e^{{x^3}}}\cfrac{d}{{dx}}({x^3}) = {e^{{x^3}}} \cdot 3{x^2} = 3{e^{{x^3}}} \cdot {x^2}$

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