class 12 maths continuity and differentiability

${x^{20}}$

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📘 Continuity and Differentiability NCERT Ex.5.7 ,Q.2,Page 183 SA

${x^{20}}$

Official Solution

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Let$y = {x^{20}}$
$\Rightarrow$ $\cfrac{{dy}}{{dx}} = 20{x^{19}}$

therefore,

$\cfrac{{{d^2}y}}{{d{x^2}}} = 20 \cdot 19{x^{18}} = 380{x^{18}}$

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