The integrating factor of differential equation
$\frac{{dy}}{{dx}} + y\tan x - \sec x = 0$ is
The integrating factor of differential equation
$\frac{{dy}}{{dx}} + y\tan x - \sec x = 0$ is
Official Solution
VVidaara Team
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Given that, $\frac{{dy}}{{dx}} + y\tan x - \sec x = 0$
Here, $P = \tan x,Q = \sec x$
$IF = {e^{\int P dx}} = {e^{\int {\tan } xdx}}$
$= {e^{(\log \sec x)}}$
$= \sec x$
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