${(y''')^2} + {(y'')^3} + {(y')^4} + {y^5} = 0$
${(y''')^2} + {(y'')^3} + {(y')^4} + {y^5} = 0$
Official Solution
VVidaara Team
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.: The highest order derivative is $y'''$ and the degree of its highest order is 2.
Therefore, the given differential equation is of order 3 and degree 2.
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