$y = \cos x + C:y' + \sin x = 0$
$y = \cos x + C:y' + \sin x = 0$
Official Solution
VVidaara Team
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NCERT & Exemplar
.: We have, $y = \cos x + C$
…(1)
Differentiating (1) w.r.t. $x$,
we get $y' = - \sin x$
$\Rightarrow y' + \sin x = 0$
Hence, $y = \cos x + C$ is a solution of the
given differential equation.
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