$\int {{{\left( {\sqrt x - \cfrac{1}{{\sqrt x }}} \right)}^2}dx}$
$\int {{{\left( {\sqrt x - \cfrac{1}{{\sqrt x }}} \right)}^2}dx}$
Official Solution
VVidaara Team
✓ Verified solution
NCERT & Exemplar
Let$I = \int {{{\left( {\sqrt x - \cfrac{1}{{\sqrt x }}} \right)}^2}dx}$
$= \int {\left( {x + \cfrac{1}{x} - 2} \right)dx} = \cfrac{{{x^2}}}{2} + \log x - 2x + C$
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