$\int {\cfrac{{{x^3} + 5{x^2} - 4}}{{{x^2}}}dx}$
$\int {\cfrac{{{x^3} + 5{x^2} - 4}}{{{x^2}}}dx}$
Official Solution
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NCERT & Exemplar
: Let$I = \int {\left( {\cfrac{{{x^3} + 5{x^2} - 4}}{{{x^2}}}} \right)dx} = \int {\left( {x + 5 - 4{x^{ - 2}}} \right)dx}$
$= \cfrac{{{x^2}}}{2} + 5x - \cfrac{{4{x^{ - 1}}}}{{ - 1}} + C = \cfrac{{{x^2}}}{2} + 5x + \cfrac{4}{x} + C$
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